2017 THREE(b)

Achievement
Question
Find the gradient of the curve y=1x1x2y = \frac{1}{x} - \frac{1}{x^2} at the point (2,14)\left(2, \frac{1}{4}\right).

*You must use calculus and show any derivatives that you need to find when solving this
problem.*
Official Answer
y=x1x2y=x^{-1}-x^{-2}
dydx=x2+2x3\dfrac{dy}{dx}=-x^{-2}+2x^{-3}
=1x2+2x3=\dfrac{-1}{x^2}+\dfrac{2}{x^3}
At x=2x=2 dydx=14+28=0\dfrac{dy}{dx}=\dfrac{-1}{4}+\dfrac{2}{8}=0
Grading Criteria

Achievement (u)

  • Correct solution with correct derivative.

Merit (r)

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Excellence T1

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Excellence T2

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Video Explanation
NCEA Level 3 Calculus Differentiation 2017 NZQA Exam - Worked Answers by infinityplusone(starts at 51:02)
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