2024 ONE(b)

Achievement
Question
A curve is defined by the equation y=(x2+3x+2)sinxy = (x^2 + 3x + 2)\,\sin x.

Find the gradient of the tangent to this curve when x=0x = 0.

*You must use calculus and show any derivatives that you need to find when solving this problem.*
Official Answer
dydx=(2x+3)sinx+(x2+3x+2)cosx\dfrac{dy}{dx}=(2x+3)\sin x+(x^2+3x+2)\cos x

x=0x=0 gives dydx=2\dfrac{dy}{dx}=2
Grading Criteria

Achievement (u)

  • Correct gradient of tangent, with correct derivative.

Merit (r)

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Excellence T1

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Excellence T2

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Video Explanation
2024 NCEA L3 Calculus Exam Walkthrough by infinityplusone(starts at 1:39)
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