2020 TWO(a)

Achievement
Question
Differentiate y=tanxx3y = \dfrac{\tan x}{x^3}.

*You do not need to simplify your answer.*
Official Answer
dydx=x3sec2x3x2tanxx6\dfrac{dy}{dx}=\dfrac{x^3\cdot\sec^2x-3x^2\tan x}{x^6}
Grading Criteria

Achievement (u)

  • Correct derivative

Merit (r)

-

Excellence T1

-

Excellence T2

-
Video Explanation
NCEA Level 3 Calculus Differentiation 2020 NZQA Exam - Worked Answers by infinityplusone(starts at 19:21)
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