2021 TWO(b)

Achievement
Question
A curve has the equation y=x2x+1y = \dfrac{x^2}{x+1}.

Find the xx-coordinate(s) of any stationary point(s) on the curve.

*You must use calculus and show any derivatives that you need to find when solving this problem.*
Official Answer
dydx=(x+1)2xx2(x+1)2\dfrac{dy}{dx}=\dfrac{(x+1)2x-x^2}{(x+1)^2}
=x2+2x(x+1)2=\dfrac{x^2+2x}{(x+1)^2}

dydx=0x(x+2)=0\dfrac{dy}{dx}=0\Rightarrow x(x+2)=0

x=0x=0 or x=2x=-2
Grading Criteria

Achievement (u)

  • Correct solutions with correct derivative.

Merit (r)

-

Excellence T1

-

Excellence T2

-
Video Explanation
NCEA Level 3 Calculus Differentiation 2021 NZQA Exam - Worked Answers by infinityplusone(starts at 33:24)
Subscribe