2013 ONE(b)

Achievement
Question
Find the gradient of the tangent to the function f(x)=ln(3xex)f(x)=\ln(3x-e^x) at the point where x=0x=0.
Official Answer
dydx=3ex3xex\dfrac{dy}{dx}=\dfrac{3-e^x}{3x-e^x} or no tangent exists

At x=0x=0 gradient =2=-2
Grading Criteria

Achievement (u)

  • Correct solution with correct derivative shown.

Merit (r)

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Excellence T1

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Excellence T2

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