2019 THREE(d)

Merit
Question
The velocity of an object is modelled by the function

v=2et+8etv = 2e^t + 8e^{-t}, for t0t \ge 0

where vv is the velocity of the object, in m s1^{-1}
and tt is the time in seconds since the start of the object’s motion.

Find the time when the acceleration of the object is 0.

*You must use calculus and show any derivatives that you need to find when solving this
problem.*
Official Answer
a(t)=2et8eta(t)=2e^{t}-8e^{-t}
a(t)=0a(t)=0
2et8et=0\Rightarrow 2e^{t}-8e^{-t}=0
2et=8et2e^{t}=8e^{-t}
e2t=4e^{2t}=4
2t=ln42t=\ln 4
t=12ln4  (=ln2=0.693)t=\frac{1}{2}\ln 4\;(=\ln 2=0.693)
Grading Criteria

Achievement (u)

  • Correct derivative.

Merit (r)

  • Correct solution with correct derivative.

Excellence T1

-

Excellence T2

-
Video Explanation
NCEA Level 3 Calculus Differentiation 2019 NZQA Exam - Worked Answers by infinityplusone(starts at 54:37)
Subscribe