2020 TWO(b)

Achievement
Question
The value of a car is modelled by the formula

V=17000e0.25t+2000e0.5t+500V = 17\,000e^{-0.25t} + 2000e^{-0.5t} + 500 for 0t200 \le t \le 20

where VV is the value of the car in dollars (\),and), and t$ is the age of the car in years.

Calculate the rate at which the value of the car is changing when it is 8 years old.

*You must use calculus and show any derivatives that you need to find when solving this
problem.*
Official Answer
dVdt=4250e0.25t1000e0.5t\dfrac{dV}{dt}=-4250e^{-0.25t}-1000e^{-0.5t}

t=8dVdt=4250e21000e4t=8\Rightarrow\dfrac{dV}{dt}=-4250e^{-2}-1000e^{-4}

=593.50=-593.50
Decreasing at \593.50$ per year.
Grading Criteria

Achievement (u)

  • Correct solution with correct derivative.
  • Units not required.
  • Interpretation not required.

Merit (r)

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Excellence T1

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Excellence T2

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Video Explanation
NCEA Level 3 Calculus Differentiation 2020 NZQA Exam - Worked Answers by infinityplusone(starts at 20:29)
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