2022 TWO(b)

Achievement
Question
Find the gradient of the tangent to the curve y=(3x22)3y = (3x^2 - 2)^3 when x=2x = 2.

You must use calculus and show any derivatives that you need to find when solving this problem.
Official Answer
y=(3x22)3y=(3x^2-2)^3
dydx=3(3x22)2(6x)\dfrac{dy}{dx}=3(3x^2-2)^2(6x)
At x=2x=2, dydx=3600\dfrac{dy}{dx}=3600
Grading Criteria

Achievement (u)

  • Correct solution with correct derivative.

Merit (r)

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Excellence T1

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Excellence T2

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Video Explanation
2022 NCEA L3 Calculus Exam Walkthrough by infinityplusone(starts at 30:45)
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