2023 THREE(c)

Merit
Question
Char goes for a ride on a Ferris wheel. As she rotates around,
her position can be described by the pair of parametric
equations :

x=52sin(πt5)x = 5\sqrt{2}\,\sin\left(\frac{\pi t}{5}\right) and y=1052cos(πt5)y = 10 - 5\sqrt{2}\,\cos\left(\frac{\pi t}{5}\right)

where tt is time, in seconds, from the start of the ride.

Find the gradient of the normal to this curve at the point when
t=6.25t = 6.25 seconds, after the start of the ride.

*You must use calculus and show any derivatives that you need
to find when solving this problem.*
Official Answer
dxdt=2πcos(πt5)\dfrac{dx}{dt}=\sqrt{2}\pi\cos\left(\dfrac{\pi t}{5}\right)
dydt=2πsin(πt5)\dfrac{dy}{dt}=\sqrt{2}\pi\sin\left(\dfrac{\pi t}{5}\right)\Rightarrow
dydx=tan(πt5)\dfrac{dy}{dx}=\tan\left(\dfrac{\pi t}{5}\right)
When t=6.25t=6.25\Rightarrow
dydx=tan(1.25π)=1\dfrac{dy}{dx}=\tan(1.25\pi)=1
Normal gradient: m=1m=-1
Grading Criteria

Achievement (u)

  • Correct expression for dxdt\dfrac{dx}{dt} AND dydt\dfrac{dy}{dt}.

Merit (r)

  • Gradient of the normal found.

Excellence T1

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Excellence T2

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Video Explanation
2023 NCEA L3 Calculus Exam Walkthrough by infinityplusone(starts at 54:28)
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