2014 THREE(e)

Excellence
Question
A cone has a radius of 20 cm and a height of 40 cm.

A cylinder fits inside the cone, as shown below.
Loading diagram...
What must the radius of the cylinder be to give the cylinder the maximum volume?
You do not need to prove that the volume you have found is a maximum.
*Show any derivatives that you need to find when solving this problem.*
Official Answer
h=402rh=40-2r
V=πr2hV=\pi r^2h
=πr2(402r)=\pi r^2(40-2r)
=40πr22πr3=40\pi r^2-2\pi r^3
dVdr=80πr6πr2\dfrac{dV}{dr}=80\pi r-6\pi r^2
dVdr=080πr6πr2=0\dfrac{dV}{dr}=0\Rightarrow 80\pi r-6\pi r^2=0
2πr(403r)=02\pi r(40-3r)=0
r=403 or 0r=\dfrac{40}{3}\text{ or }0
r=403 cmr=\dfrac{40}{3}\text{ cm}
Grading Criteria

Achievement (u)

  • Correct derivative for an incorrect but relevant expression for VV.

Merit (r)

  • A correct expression for dVdr\dfrac{dV}{dr}

Excellence T1

  • A correct solution. Units not required.

Excellence T2

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